Curium-243 has a half-life of 28.5 days. in a sample of 5.6 grams of curium-243, how many grams will remain after 12 days? a. 1.08g b.2.8g c.4.18g d.2.09g e.5.6g

The correct answer option is C. 4.18 g.

Step-by-step explanation:

We are given that Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243 and we are to find how many grams will remain after 12 days.

To find the number of remaining grams, we will use the following formula:

where t is the time and h is the half life.

So substituting in the given values to get:

Therefore, 4.18 grams of curium-243 will remain after 12 days.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

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