The number of bagels sold daily for two bakeries is shown in the table. bakery a bakery b 53 34 52 40 50 36 48 38 53 41 47 44 55 40 51 39 based on these data, is it better to describe the centers of distribution in terms of the mean or the median? why? select the correct answer below. mean, because there are no outliers to affect the data mean, because the distribution is perfectly symmetric for both bakeries median, because the distribution for bakery b is not symmetric median, because there are outliers that affect both data sets

can someone answer this question plz

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.