Find all the zeros of each equation 7x^2-144=-x^4 x^3-x^2+5x-5=0

1.     3, -3, 4i, -4i.

2.    1, √5i, - √5i.

Step-by-step explanation:

1.   7x^2 - 144 = -x^4

x^4 + 7x^2 - 144 = 0

Let y = x^2,  then we have:-

y^2 + 7y - 144 = 0

(y + 16)(x - 9) = 0

y = -16 or 9.

So x +/- √9  or +/- √-16

x = 3, -3, 4i, -4i  (answer).

2.   x^3-x^2+5x-5=0

f(1) = 1 - 1 + 5 - 5 = 0

Therefore x = 1 is a zero.

Therefore x - 1 is a factor of the function.

To find the other zeroes we divide  the function by x - 1:-

        x^2 + 5    < is the result.

x - 1 )  x^3 - x^2 + 5x - 5

         x^3  - x^2

                      5x - 5

                      5x - 5.

So we have:-

x^2 + 5 = 0

x^2 = -5

x = +/- √5 i.

do you have a picture of the table

answer: 16

step-by-step explanation: first you would add 6+6 which equals 12 then add 2+2 which equals 4. then add 12 + 4 which is 16.

hope this ^_^