Idk how to solve this problem. what is the equation of a line that is parallel to 4x+3y=12 and passes through the point (3, 4) ? enter your answer in the box.

Hello from MrBillDoesMath!

y = (-4/3)x + 8

Discussion:

The given line 4x + 3y = 12 is equivalent to

3y = 12 - 4x =>                          (divide both sides by 3)

y = 4 - (4/3)x

slope of line = m = -(4/3)

The slope of the parallel line is the same as that of the given line so its equation is

y = (-4/3)x + b

As this line passes through the point (3, 4)

4 = (-4/3)(3) + b =>

4 = -4 + b =>              (adding 4 to both sides)

4 + 4 = b =>

b = 8

Hence the equation of the parallel line is y = (-4/3)x + 8

Thank you,

MrB

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

b

step-by-step explanation: