Using the figure of the bulseye above, what is the probability that a shooter will hit the 3rd ring on his first attempt and the bullseye on his second attempt? express your answer as a decimal rounded to the nearest hundredths place

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

no solution

step-by-step explanation:

there is not enough information in the problem to solve.

7,24

step-by-step explanation:

other answer is correct. i had used the radius of the radius somehow. a website: