Me
30 points
show you work

1) In the following given figure we have that line segment P'Q' is parallel to line segment PQ.

so, slope of P'Q' where coordinates of P' is (m,n+) and Q' is (j,k+)

So, slope of P'Q'

The coodinates of P are (m,n) and that of Q are (j,k)

slope of PQ

Hence, slope of both the lines are equal.

(a) Since, by translation we mean there is a fixed number 's' such that every point on one line is translated by 's' units on the second line.

i.e. each corresponding points between the two lines are translated by a fixed unit.

(b) the slope of line 'r' is same as slope of the line segment PQ

slope of line r

(c)The slope of line 's' is same as slope of line segment P'Q'

Hence, slope of line s

(d) q is a vertical translation of line 's' 3 units down

P'' is a image of P' .

so the coordinates of P'' is given by: (m,n+-3)

its not b

step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2