In parallelogramefgh , ej=x2−4 and jg=3x . what is eg ? 4 6 12 24 quadrilateral e f g h with lines bisecting the shape from e to g and from f to h, point where line segments e g and f h intersect is labeled j

Option D is correct.

Side EG = 24 units.

Step-by-step explanation:

As per the given statement:

In a parallelogram EFGH

and

By Properties of parallelogram:

Here, EG and FH are diagonals;

EG = EJ + JG              

by properties of parallelogram:

EJ =JG

Substitute the given values we have;

⇒

⇒

⇒

⇒

By zero product property;

x = -1 and x = 4

⇒  (always used positive number for sides)

Then;

EG = JG+JG = 2JG

units

Therefore, the diagonal EG = 24 units.