The object of the game is to toss a beanbag in the circular hole of a 48-by-24-inch board. if the diameter of the circle is 6 inches, what is the geometric probability an object will hit the circle on the board? assume that the object will hit the board.

Geometric probability of an object hitting a circular hole is 0.0245.

Step-by-step explanation:

We have given,

A board of size 48 by 24 inch. There is a circular hole in the board having diameter 6 inches.

So,

Area of a board = 48 × 24 = 1152 square inches

And area of circular hole = π×r²   {where r = diameter/2  = 6 / 2 = 3 inches}

Area of circular hole = π×3² = 9π = 28.27 square inches

Now, we need to find the geometric probability of an object will hit the circle.

Geometric probability =  Area of circular hole / Area of board

Geometric probability =

Geometric probability = 0.0245

hence geometric probability of an object hitting a circular hole is 0.0245.

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3