The length of bills backyard swimming pool is 60 feet longer than the width of the pool. the surface area of the water is 1600 square feet . what is the width and length of the pool

The width is 20 ft and the length is 80 ft

Step-by-step explanation:

Area = l * w

l = w +60

SA = 1600 ft^2 ( which is the regular area)  The surface area of the water is just what is on top  which is length times width

1600 = l*w

Substitute in l = w+60

  1600       = (w+60) *w

Distribute the w

1600 = w^2 +60w

Subtract 1600 from each side

1600-1600 = w^2 + 60w -1600

0 =  w^2 + 60w -1600

Factor

0=(w-20) (w+80)

Using the zero product property

w-20=0   w+80 =0

w=20  or w=-80

The width cannot be negative   so

w=20

Now we need to find the length

l = w+60

l = 60+20

l =80

my answer got deleted but it's a

step-by-step explanation:

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.