During the first hour of operation the farm stand owner sold 15% of the apples he had. on the second hour he sold 20% of the remaining apples. on the third hour he sold 25% of the remaining apples, and so on, selling 5% more each following hour, if during the second hour 25.5 kg of apples were sold, how many kilograms of apples will be sold during the fourth hour of operation?

 3.825 kg apples.

Step-by-step explanation:

Let x kg be the amount of apples stand owner had initially.

We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:

On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.

During the second hour 25.5 kg of apples were sold, so we can set up an equation as:

So, stand owner had initially 150 kg of apples.

On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x

As remaining apples were sold 5% more each following hour.

Let us substitute x=150 into above equation we will get,

Therefore, 3.825 kg of apples were sold during the 4th hour.

answer: the answer is (b) amie should have multiplied

step-by-step explanation: given a sphere and a cylinder with same radius and height.

let, 'r' be the radius of the cylinder and sphere and 'h' be the height of the cylinder. according to the question,

r = h.

now, the volume of the sphere will be

and the volume of the cylinder will be

therefore, we have

thus, ammie should have multiplied the volume of the sphere

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.