What is the domain of the function f(x) = 2/5 sq x ?

d)  All real numbers greater than or equal to 0.

Step-by-step explanation:

The given function f(x)=2/5 √x

Inside the square root, we will not have the negative number.

If we have the negative number inside the square root, then it will be imaginary number.

Therefore, domain is the all the real numbers greater than or equal to 0.

Here 0 is possible because square root (0) = 0.

d) All real numbers greater than or equal to 0.

Thank you.

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94