Mathematics, 26.06.2019 07:00, Drea1385

An airplane's change in altitude before landing is shown in the table. what equation represents this change in altitude? soon

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answered: babbity2009

The equation that represents this change in altitude is $\sigma = -4000m +39000$ and this can be determined by using the point-slope form of the line.

Given :

The data is in the table.

Give that at m = 1 min, $\sigma = 35000$ ft and at m = 2min, $\sigma = 31000$ . Then using the point-slope form of the line which is given by:

$\dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}$ --- (1)

where (x_1,y_1) and (x_2,y_2) are points on the line.

Now, put the value of (x_1,y_1) and (x_2,y_2) in equation (1).

$\dfrac{\sigma-35000}{m-1}=\dfrac{31000-35000}{2-1}$

$\dfrac{\sigma-35000}{m-1}=\dfrac{-4000}{1}$

$\sigma-35000={-4000}{(m-1)}$

$\sigma - 35000=-4000m+4000$

$\sigma = -4000m +39000$

The equation that represents this change in altitude is $\sigma = -4000m +39000$ and this can be determined by using the point-slope form of the line.

For more information, refer to the link given below:

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answered: fifthward92

y =-4000x+39000

Step-by-step explanation:

Minutes (m) Altitude(a)

1 35000

2 31000

3 27000

4 23000

Slope : $m =\frac{y_2-y_1}{x_2-x_1}$ ---A

(x_1,y_1)=(1,35000)

(x_2,y_2)=(2,31000)

Substitute the values in A

$m =\frac{31000-35000}{2-1}$

m =-4000

(x_1,y_1)=(3,27000)

(x_2,y_2)=(4,23000)

Substitute the values in A

$m =\frac{23000-27000}{4-3}$

m =-4000

Since the slopes are same.

Thus the given table represents the linear function.

Now we will use two point slope form top obtain the required equation

$y-y_1 =\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

(x_1,y_1)=(1,35000)

(x_2,y_2)=(2,31000)

$y-3500 =\frac{31000-35000}{2-1}(x-1)$

y-3500 =-4000x+4000

y =-4000x+4000+35000

y =-4000x+39000

Thus Option D is correct.

The equation represents this change in altitude is y =-4000x+39000

answered: Guest

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean = $\frac{2+3+4+5+6+7+8+9}{8}=\frac{44}{8}=5.5$

also, median= $\frac{5+6}{2}=\frac{11}{2}=5.5$ , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean = $\frac{2+3+4+5+6}{5}=\frac{20}{5}=4$

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

answered: Guest

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this