Joanna buys one kilogram of french roast and one kilogram of boxer blend from the java hut. jacob buys two kilograms of french roast and three kilograms of boxer blend. if joanne spends $18 for her purchase, and jacob spends $46 for his, what is the price of one kilogram of boxer blend coffee?

9514 1404 393

  $10

Step-by-step explanation:

Let r and b represent the costs of 1 kg of French roast and Boxer blend, respectively. Then the two purchases can be written as ...

  b +r = 18 . . . . . . . Joanna's purchase

  3b +2r = 46 . . . . Jacob's purchase

Subtracting twice the first equation from the second gives us the desired price.

  (3b +2r) -2(b +r) = (46) -2(18)

  b = 10 . . . . . simplify

The price of 1 kg of Boxer Blend coffee is $10.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3