Two thirds of a number plus 17 is at least 29

x ≥ 18 is your answer

Step-by-step explanation:

Let "a number" = x

(2/3)x + 17 ≥ 29

Isolate the variable (x). Do the opposite of PEMDAS (Parenthesis, Exponent (& root), Multiplication, Division, Addition, Subtraction).

First, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

Next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

Simplify. Multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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