The cargo box of an 18-wheeler truck has an inside length of 39.6 feet, width of 7.6 feet, and a height of 8.8 feet. what is the carrying capacity (volume) of the cargo box of his truck? explain your thinking.

2,648.448 cubic feet

Step-by-step explanation:

The cargo box of a truck is a rectangular prism. The volume of a rectangular prism is l*w*h.

If the length is 39.6 ft, the width is 7.6 ft and the height is 8.8 ft then the volume is (39.6)(7.6)(8.8) = 2,648.448 cubic feet

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6