The coordinate plane below represents a town. points a through f are farms in the town.

Part A)

You can isolate Point E , by drawing a solid horizontal line at Y4, which be be the equation: y ≥ 4

Then in order to isolate point D you need an angles line, since you already have a horizontal line at Y 4 use this as the Y intercept, which would mean the point is (0,4) give the line a slope of 1 and you can reverse the first point to get the other point ( -4, 0), this will be a solid line to include the y intercept of 4:

This equation would be: y ≥ x + 4

Now see attached picture showing the two lines and shaded area would include D and E

Part B)

To verify D and E are solutions, find their X and Y coordinates:

D is at (-4,2)

So looking at the second equation from Part A replaxe x with -4: y = -4 + 4 = 0 and the Y is 2, which is greater tah 0, so D is a solution.

E is at (-1,5) and using the first equation from Part A, 5 is greater than 4, so this is also a solution.

Part C)

You can give X a number and solve for Y. Do this twice to create 2 points, then you can draw a line connecting the two points to see which farms you can have chickens on.

At X 0, Y > -4, so your first point is (0,-4)

At X 1, Y> -1, your second point is (1,-1)

See the second picture with just the red shaded area. Any farm located in that area can raise chickens.

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