Being 360 meters apart, two dogs started running towards each other at the same time. in 20 seconds the distance between them was 200 meters. how fast each of them ran if one of them ran faster by 3 meters per second?

Speed of one dog is 2.5 m/s and other dog is 5.5 m/s.

Step-by-step explanation:

Total distance between the two dogs = 360 m

Let the speed of one dog be x m/s, then the speed of second dog will be x+3 m/s.

Then total speed of two dogs = x+x+3 = 2x+3

Times = 20 seconds

After 20 seconds, distance left between them = 200 m

Distance traveled by the two dogs in 20 seconds = 360 m - 200 m

                                                                                    = 160 m

We know, Speed  =

          2x+3 =  

              2x = 8-3 = 5

              x =  2.5 m/s

Speed of first dog = 2.5 m/s

Speed of second dog = x+3 = 2.5 +3

                                     = 5.5m/s

Speed of one dog is 2.5 m/s and other dog is 5.5 m/s.

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages