Y- 5 = 0.5x2 + 6x - 3 how many x-intercepts does the graph of this quadratic have? two x-intercepts one x-intercept no x-intercepts

Step-by-step explanation:

The given equation is y - 5 = 0.5x² + 6x - 3

We have to find the number of x - intercepts the graph of this equation will make.

For x-intercepts we will put y = 0

so 0 - 5 =0.5x² + 6x - 3

     0.5x² + 6x - 3 + 5 = 0

   0.5x² + 6x + 2 = 0

      x² + 12x + 4 = 0

We know if a quadratic equation is ax² + bx + c = 0

and b² - 4ac > 0 there will be two real roots.

In this equation b = 12, C = 4 and a = 1 (12)² - 4 × 4 = 144 - 16

                                                         = 128 > 0

Therefore, there will be two intercepts of x

shift 4 units up, and 1 unit left.

it will translate f(x) = 3^x to g(x) = 3^(x+1) + 4

question 1: step-by-step explanation:

1/4 of 84 = 84÷4= 21