The solution set of the equation |x - 1| = 3 is {-2, 4} {-3, 3} {-4, 2}

{-2, 4}

Step-by-step explanation:

|x - 1| = 3

There are two cases, one positive and one negative

x - 1 = 3  and  x-1 = -3

Add 1 to each side

x-1+1 = 3+1    x-1+1 = -3+1

x =4                 x = -2

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180