The vertex of the graph of y = -4(x + 3)2 + 2 is

The vertex is (-3, 2)

The equation y = -4(x + 3)^2 + 2 can be written as y = -4(x - (-3))^2 + 2

I rewrote x+3 as x - (-3)

Compare y = -4(x - (-3))^2 + 2 with the general template y = a(x-h)^2 + k

Note how

a = -4

h = -3

k = 2

So the vertex is (h,k) = (-3, 2)

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

answer:

c) the x-coordinate of the center of the circle increases by 3