Simply each expression. leave no negative or zero exponents (mcc.8.ee.1) a. 6/0 b) 5/6•5/8 c) 7/10/7/4d) 4-3 e) (g2)5 f) y/5 y|5

Hello from MrBillDoesMath!

a. 6/0 is undefined  

b. 25/48

c. 2/5

d 1

e) ??? question is not clear

f)   y^2/25

Discussion:

The problem statements are not particularity clear.  Here are my interpretations:

a. Undefined as division by division is not a real (or complex) number

b.  5/6 * 5/8  = (5/6)*(5/8) = (5*5)/(6*8) = 25/48

c. 7/10/7/4   -- a model of confused thinking. I think it means

                    (7/10)/ (7/4) = (7/7) * (4/10) = 1 * (4/10) = 2/5

d. 4-3 = 1

e. (g2)5       -- unclear what this even means

f. I think this is interpreted as (y/5)*(y/5) = y^2 / 25

Good luck!

Thank you,

MrB

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204