What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

k =3

Step-by-step explanation:

f(x) = 112 -kx

Let x = -3

f(-3) =112 -k(-3)

We know that it equals 121

121 = 112 +3k

Subtract 112 from each side

121-112 =112 -112 +3k

9 = 3k

Divide each side by 3

9/3 = 3k/3

3 =k

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

there is no question content here, but you for the free points! : d