Aplan for a house includes rectangular room with an area of 60 square meters and a perimeter of 32 meters. what are the length and width of the room?

When width of room is 6 meters then length is 10 meters

When width of room is 10 meters then length is 6 meters.

Step-by-step explanation:

Given : The area of rectangular room is 60 square meters .

The Perimeter of room is 32 meters.

To Find : Length and width of room

Solution :

Let length of room be x meters

Let width of room be y meters.

Now , Formula of area of rectangle is:

Area of rectangle = Length * Width

Since we are given that area of rectangular room is 60 square meters .

⇒ 60 = x * y   ----(a)

Now Formula of perimeter of rectangle is :

Perimeter of rectangle = 2(length + width)

Since we are given that Perimeter of room is 32 meters.

⇒32 = 2(x+y)

⇒32= 2x+2y ----(b)

Now substitute the value of x from (a) in (b)

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒

⇒ y-6=0 and y-10=0

⇒ y=6 and y =10

Now calculate value of x corresponding to these value of y by putting values of y in a

When y = 6

⇒

⇒

When y = 10

⇒

⇒

So, when y= 6 then x= 10 and when y= 10 then x = 6

Thus when width of room is 6 meters then length is 10 meters

Thus when width of room is 10 meters then length is 6 meters.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

why are you giving so many marks make your marks less and make a question list so that i can understand your question very nicely