Find the range for the measure of the third side of a triangle given the measures of two sides are 5 m and 11 m.

a, b, c - sides of a triangle

a + b > c

a + c > b

b + c > a

We have a = 5m and b = 11m. Substitute:

5 + 11 > c

16 > c → c < 16

5 + c > 11        subtract 5 from both sides

c > 6

11 + c > 5        subtract 11 from both sides

c > -6

c < 16 and c > 6 and c > -6

Thereofre your answer is 6m < c < 16m

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: