Drag the tiles to the correct boxes to complete the pairs. match the systems of equations with their solutions. solution (-31, -56) (51, 26) (47, 33) (-17, -36) system of linear equations 1.) x-y = 25 , 2x+3y = 180 2.) 2x-3y = -5 , x+y/11 = 50 3.) x-y = 19 , -2x+y/6 = 28 4.)2x-y= 6 , x-305/3 = 2y

4, 1, 2, 3 . . . . . the systems of equations corresponding to the given solutions, in order

When there are this many to do, it is convenient to let a calculator or spreadsheet help. Most will work best with integer coefficients, so the pairs of equations can be written ...

1.

2.

3.

4. Here, we have a problem. The given equations don't match any solutions. The only remaining solution is (-31, -56), and it gives a value of -6 for the first equation, not 6. The second equation needs parentheses to make it work. We think your problem is ...

... 2x -y = -6, (x -305)/3 = 2y

Recast the way the others are above, these equations become ...

Comment on solution to systems of equations

The solution to ...

is ...

This is a modified form of Cramer's rule. It is modified in that both numerator and denominator have the terms swapped (are the negative of the terms in the classic Cramer's rule). This form can be easy to remember, as the pattern is fairly simple. (Look at where the coefficients are in the equations. Use your spatial memory to remember the pattern.)

Example:

Applying these solution equations to system (4), we have ...

... x = ((-1)·305 -(-6)(-6))/((-1)·1 -(-6)·2) = -341/11 = -31

... y = ((-6)·1 -305·2) = -616/11 = -56

Step-by-step explanation:

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.