Mathematics, 26.06.2019 21:00, joelpimentel
Which function has a simplified base of 4^sqrt 4 ? f(x) = 2^(3 sqrt 16) f(x) = 2^(3 sqrt 64) f(x) = 4(^3 sqrt 12 )^ 2x f(x) = 4^(3 sqrt 64)^ 2x
Answers: 2
![4^{(\sqrt[3]{64} )^{2x}}](/tpl/images/0020/8703/f481d.png)
.![f(x) = 2^{(\sqrt[3]{16} )}](/tpl/images/0020/8703/b63c2.png)
![2^{(\sqrt[3]{64} )}](/tpl/images/0020/8703/3f93a.png)
![4{(\sqrt[3]{12})^{2x}}](/tpl/images/0020/8703/d93aa.png)
![2^{(\sqrt[3]{16} )}](/tpl/images/0020/8703/e4d5f.png)
, we get ![2^{(2\sqrt[3]{2} )}](/tpl/images/0020/8703/b4b40.png)
.![4\left(\sqrt[3]{12}\:\:\right)\left(\sqrt[3]{12}\:\:\right)^x=4\left(\sqrt[3]{12\cdot 12}\right)\:^x=4\left(2\sqrt[3]{18}\right)^x](/tpl/images/0020/8703/2a199.png)
.![4^{\left(\sqrt[3]{64}\:\right)^{2x}}=4^{\left(4\:\right)^{2x}}=\:4^{16^x}.](/tpl/images/0020/8703/fdb2e.png)
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Which function has a simplified base of 4^sqrt 4 ? f(x) = 2^(3 sqrt 16) f(x) = 2^(3 sqrt 64) f(x) =...
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