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![\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \log_0(3)=x\implies 0^x=3~\hfill \stackrel{\textit{so there's no \underline{x} value that will satisfy that}}{0^{anything}=0\qquad \qquad 0^0=unde fined} \\\\\\ \log_1(3)=x\implies 1^x=3\hfill \stackrel{\textit{so there's no \underline{x} value that will satisfy that either}}{1^{anything}=1}](/tpl/images/0020/9804/4fc7f.png)
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Mathematics, 21.06.2019 15:20, devenybates
In exponential growth functions, the base of the exponent must be greater than 1,how would the function change if the base of the exponent were 1? how would the fiction change if the base of the exponent were between 0and 1
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