Harry is trying tq solve the equation y=2x^2 -x-6 using the quadratic formula he has made an error in one of the steps below

Hello :

y = 2x² - x -6

y = 2 ( x² - 1/2 x - 3)

y = 2 (x² -1/2 x + 1/16 -1/16 -3)

y = 2 (( x - 1/4 )² - 49/16)  the quadratic formula

y = 0 :  ( x - 1/4 )² - 49/16 = 0

( x - 1/4 )² - (7/4)² = 0

( x -1/4-7/4)( x -1/4+7/4)=0

(x -2)(x + 3/2) = 0

x - 2 = 0 or x + 3/2 =0

x = 2 or x = - 3/2

dd

step-by-step explanation:

dd

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).