The center of a circle of a circle is at q(0,6), a radius is drawn from q to p(4,6). what are the coordinates of the endpoint of the diameter that includes segment pq? a. (0,2)b. (0,10)c. (-4,6)d. (6,-4)

(-4,6) or C

Step-by-step explanation:

Givens

x_center = 0y_center = 6x_center = (x1 + x2)/2y_center = (y1 + y2)/2x1 = 4y1 = 6Solve for x2 and y2

Solution

x_center = (4 + x2) / 2 = 0                Multiply both sides by 20*2 = (4 + x2)*2                                 Divide by 20 = 4 + x2                                           Subtract 4 from both sides.-4 = x2You can now declare an answer. The answer must be C

Discussion

A and B both have an x value of 0. Not correct.D is backwards.Just to make sure, we'll solve for y2y_center = 66 = (y1 + y2)/2         Multiply by 26*2 = y1 + y2          Comgine12 = 6 + y2              Subtract 6 from both sides12-6 = y2y2 = 6Which is just what C says.