Take a look at teen 1's initial polynomials for three layers of hills. teen 1 has described what he thinks each modification to the initial polynomial will do. sketch each curve (in a different color, preferably). (you will be asked to find and repair mistakes in the next section.) (6 points: 2 points for each curve) hill 1: my first layer needs three peaks. i chose three points on the x-axis (the three zeros), and then i wrote each as a binomial to create the first polynomial. f(x) = (x – 1)(x – 3)(x – 4) hill 2: my second layer should be a useful transformation of the first. using the first polynomial as the base, i multiplied it by to flip it and make the hills steeper. then, i added 3 to shift it to the right. f(x) =– (x – 1)(x – 3)(x – 4) + 3 hill 3: this hill should be a shallow parabola that will rise up in the foreground of my picture. f(x) = 4(x–)(x – 5)

This question is based on the graph. Therefore, the errors are:

(1) Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).

(2) Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).

(3) Error is that, multiplying by four makes a steeper slope (not a shallow slope).

Given:

Take a look at teen 1's initial polynomials for three layers of hills. Teen 1 has described what he thinks each modification to the initial polynomial will do.

According to the question,

Attachment of each curve, is below.

(1) I chose three points on the x-axis (the three zeros), and then I wrote each as a binomial to create the first polynomial. F(x) = (x – 1)(x – 3)(x – 4).

Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).

(2) Using the first polynomial as the base, I multiplied it by to flip it and make the hills steeper. Then, I added 3 to shift it to the right. F(x) =– (x – 1)(x – 3)(x – 4) + 3.

Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).

(3)This hill should be a shallow parabola that will rise up in the foreground of my picture. F(x) = 4(x–)(x – 5).

Error is that, multiplying by four makes a steeper slope (not a shallow slope).

Therefore, the errors are in each question,

(1) Error is that, three zeros (x-intercepts) does not make 3 peaks (vertices).

(2) Error is that, multiplying it by a negative is a reflection (not a steeper slope). Adding three on the outside of the factors is a vertical shift up (not a horizontal shift to the right).

(3) Error is that, multiplying by four makes a steeper slope (not a shallow slope).

For more details, prefer this link:

link

See attachment for graphs

1) Error: 3 zeros (x-intercepts) does not make 3 peaks (vertices)

2) Errors: Multiplying it by a negative is a reflection (not a steeper slope). Adding 3 on the outside of the factors is a vertical shift up (not a horizontal shift to the right).

3) Error: Multiplying by 4 makes a steeper slope (not a shallow slope).

option a is correct.

step-by-step explanation:

scale factor: it is used to find proportional measurements.

proportions means having the same ratio.

scale factor is the ratio of the model measurement to the actual measurement in a simplest form.

or we can say that the ratio of any two corresponding lengths in two similar geometric figures

if the scale factor is more than 1, then it is an enlargement,

if the scale factor less than 1, then it is a reduction.

given the two geometric figure:

by definition of proportions, we have