Picture attached given that tan 0=-1, what is the value of sec0 for 3pi/202pi?

   = -sqrt(2)

Step-by-step explanation:

tan theta = -1

we know tan = opposite/ adjacent

So opposite/adjacent = -1

Multiply by adjacent on each side

opposite = - adjacent

We also know from pythagorean theorem that

opposite ^2 + adjacent ^2 = hypotenuse ^2

Substituting in for adjacent

opposite ^2 + (-opposite ) ^2 = hypotenuse ^2

opposite ^2 + opposite ^2 = hypotenuse ^2

2 opposite ^2 = hypotenuse ^2

 Taking the square root on each side

sqrt(2 opposite ^2)   =  sqrt(hypotenuse ^2)

sqrt(2) opposite = hypotenuse

We are now set to find the sec

sec theta = hypotenuse / adjacent

               = sqrt(2) opposite/ adjacent

Replace the opposite = -adjacent

                 = sqrt(2) (-adjacent)/adjacent)

                 = -sqrt(2)

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

y = i/2 xtnop + (3i/2 tnop+ 1)

step-by-step explanation:

the picture is the step by step explanation.