Find their perimeter and the area of trapezoid efgh. show all work needed to complete this problem. a=1/2(b1+b2)•h

Hello from MrBillDoesMath!

Area =  28

Perimeter =  14 + 2 sqrt(17)

Discussion:

In our case

       b1 =  length of EH = 3 - (-3) =  3 + 3  = 6

       b2 = length of FG = 4 - (-4) = 4 + 4 = 8

       h =  2- (-2) = 2 + 2 = 4

So

Area = A = (1/2)h(b1+b2) = (1/2)(4)(6 + 8) = 2(14) = 28

Perimeter = length of EH + length FG + length of EF + length of HG

                =           6           +     8           +   ?                 +     ?

From the Pythagorean theorem

HG = sqrt ( 1^2+ 4^2) = sqrt(17)

Similarly

EF = sqrt(17)

So Perimeter =

                       6              +       8             + sqrt(17)         + sqrt(17)

                      = 14 + 2 sqrt(17)

Thank you,

MrB

answer: i'm not sure

step-by-step explanation:

is only a line? i think so