For which value of x is the row in the table of values incorrect? the function is the quadratic function y=3/4x^2

The row with x = 2 and y = 4 is incorrect. The y value should be y = 3 when x = 2.

Explanation:

Fractions can be a bit of a pain, so I'm going to be converting to decimal form to help with the computation; however, I will convert the y value results to mix number form so that it matches what the table shows.

Keep in mind that 3/4 = 0.75 when you use a calculator or long division. So a number like 2.75 means 2 & 3/4 (two and three quarters)

Let's check the first row. Plug in x = 0 and it leads to...

y = (3/4)*x^2

y = (3/4)*0^2

y = (3/4)*0

y = 0.75*0

y = 0

This shows us that row 1 is correct. When x = 0, y = 0 leading to (x,y) = (0,0).

Repeat the same basic outline of steps, but now use x = 2

y = (3/4)*x^2

y = (3/4)*2^2

y = (3/4)*4

y = 0.75*4

y = 3

So instead of 4, the proper y value is y = 3 when x = 2. This means row 2 is the answer (the row that has the incorrect values).

For the sake of completeness, let's see if the third row is correct or not. Plug in x = 3

y = (3/4)*x^2

y = (3/4)*3^2

y = (3/4)*9

y = 0.75*9

y = 6.75

y = 6 & 3/4

We see that x = 3 points to y = 6 & 3/4, so we have the correct values in this row. We can cross this off the list of choices.

Finally, let's check x = 5

y = (3/4)*x^2

y = (3/4)*5^2

y = (3/4)*25

y = 0.75*25

y = 18.75

y = 18 & 3/4

We get the proper y value. So we can also cross this off the list.

to rewrite a literal equation you may need to divide by a number, or by a variable.

hope i .