Find the values for a and b that would make the equality true -5(3x^2+5x+b)=ax^2-25x+45

a = - 15 and b = - 9

Step-by-step explanation:

distribute the left side

- 15x² - 25x - 5b

For - 15x² - 25x - 5b = ax² - 25x + 45

Then the coefficients of like terms must be equal, hence

comparing coefficients of x² term ⇒ a = - 15

comparing constant term ⇒ - 5b = 45 ⇒ b = - 9

a = -15,   b = -9

Step-by-step explanation:

-5(3x² + 5x + b) = ax² - 25x + 45

-15x² - 25x - 5b = ax² - 25x + 45       distributed -5 on left side

Notice that the middle terms (-25x) are equal, so the the remaining terms will also be equal.

-15x² = ax²  ⇒  -15 = a

 -5b = 45   ⇒   b = -9

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

the formula for the equation of a circle is (x – h)2+ (y – k)2 = r2, where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle. if a circle is tangent to the x-axis at (3,0), this means it touches the x-axis at that point.