Plz do asap need like now me plz what is the equation of this graphed line? y = mx + b m is the slope b is the y intercept (where does the line cross the y - ordered pair) x and y can be a point on the line m = y2 - y1/x2 - x1 a graph with a line running through coordinates (-4, -6) and coordinates (2, 6) enter your answer in slope-intercept form in the box.

y = 2x+2

Step-by-step explanation:

When we have 2 points, we can find the slope from

m = (y2-y1)/(x2-x1)

   = (6--6)/(2--4)

   = (6+6)/(2+4)

   = 12/6

  = 2

The slope is 2

We can use the point slope form of the equation for a line

y-y1 = m(x-x1)

y-6 = 2(x-2)

We need to get this in slope intercept form

Distribute the 2

y-6 = 2x-4

Add 6 to each side

y-6+6 = 2x-4+6

y = 2x+2

y = 2x + 2

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + b ( m is the slope and b the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 4, - 6) and (x₂, y₂ ) = (2, 6)

m = = = 2, hence

y = 2x + b is the partial equation

to find b substitute either of the 2 points into the partial equation

using (2, 6), then

6 = 4 + b ⇒ b = 6 - 4 = 2

y = 2x + 2 ← equation in slope-intercept form

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length