From 19801980 to 20002000, the annual profit of a company was determined by subtracting from \$625{,}000$625,000 the product of \$25{,}000$25,000 and the number of years either before or after 19901990. which of the following equations below could be used to determine in which year, xx, the profit was \$550{,}000$550,000? a.550−25∣x−1990∣=625b.625 - 25 | x - 1990 | = 550625−25∣x−1990∣=550c.625 +25 | x - 1990 | = 550625+25∣x−1990∣=550d.625 +25 | x + 1990 | = 550625+25∣x+1990∣=550

b) 625 - 25 |x - 1990| = 550

Step-by-step explanation:

According to the question,

The annual profit of a company was determined by subtracting from $625,000 the product of $25,000 and the number of years either before or after 1990.

That is, On  x year the total profit is,

P(x) =  625,000 - 25,000 |x - 1990|

But again according to the question,

On x years the profit is $ 550,000

Thus, 625,000 - 25,000 |x - 1990| = 550,000

⇒ 625 - 25 |x - 1990| = 550 ( by dividing both sides by 1000)

Therefore, Option b) is correct.

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24

table 3 represents a direct variation function. : )