Huma, hubna and seema received a total of ₨2,016 as monthly allowance from their mother such that seema gets 12 of what huma gets and hubna gets 123 times seema’s share. how much money do the three sisters get individually? i need correct answer no signs used

Huma's share =Rs x =  Rs. 1.35392881

Seema's share =Rs. 12x =  Rs (12 *  1.35392881) = Rs. 16.2471457

Hubna's share =Rs. 123*12x =  Rs. (123*16.2471457) = Rs. 1998.39892

Step-by-step explanation:

Given :

Huma , Hubna and Seema received a total of ₨2,016 as monthly allowance from their mother.

Seema gets 12 of what Huma gets

Hubna gets 123 times Seema’s share

To find : How much money do the three sisters get individually?

Solution :

Let  Huma's share be Rs. x.

Since we are given that Seema gets 12 of  Huma's share

⇒ Seema's share = Rs 12x.

Since we are given that Hubna gets 123 times Seema’s share

⇒Hubna's share = Rs. (123 * 12x) = Rs. 1476x.

We are given that they received together Rs. 2016 in total .

⇒

⇒

⇒

⇒

Thus Huma's share =Rs x =  Rs. 1.35392881

Thus Seema's share =Rs. 12x =  Rs (12 *  1.35392881) = Rs. 16.2471457

Thus Hubna's share =Rs. 123*12x =  Rs. (123*16.2471457) = Rs. 1998.39892

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240