Mathematics, 27.06.2019 01:30, TimothyYash6684

Suppose we want a 90% confidence interval for the average amount spent on entertainment (movies, concerts, dates, etc.) by freshman in their first semester at a large university. the interval is to have a margin of error of $2, and the amount spent has a normal distribution with a standard deviation s = $30. the number of observations required is closest to a) 25. b) 30. c) 609. d) 865.

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Suppose we want a 90% confidence interval for the average amount spent on entertainment (movies, con...