What is the equation of the line that is perpendicular to -x + y = 7 and passes through (-1, -1)? a. -x + y = 2 b. -x – y = 2 c. x – y = 2 d. -x – y = 0 e. x + y = 0

We have y = x + 7; the slope of this line is m1 = 1;

Because the lines are perpendicular, we have m1 · m2 = - 1;

Then m2 = -1;

The equation of the second line, which passes through (-1 ,-1) and have the slope m2 = -1 is:

y - (-1) = (-1)( x - (-1));

y - 1 = (-1)( x + 1 );

y - 1 = -x - 1;

y + x = 0;

The correct answer is E. x + y = 0;

Step-by-step explanation:

5.25 ounces

step-by-step explanation:

divided 3/4 and 6

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)