The concentration of the mixture obtained by mixing two solutions, a and b, is 6 2/3 %. the concentration of the second mixture obtained by mixing the same two solutions is 16.7%. find the concentration of each of the solutions a and b, if the first mixture is obtained by mixing them in 2: 7 ratio and the second is obtained by mixing them in 7: 3 ratio.

Concentration of solution A = 23%

and concentration of solution B = 2%

Step-by-step explanation:

Lets get started

lets say that we concentration of solution A be x% and concentration of second solution be y%

we also know that first mixture is obtained by mixing them in ratio of 2:7

so linear equation representing this situation can be written as:

2(x%)+7(y%)= 9(6.66%)    

changing percentage to decimal we get,

.02x+.07y=9(.0666)

.02x+.07y = 0.6          (equation 1 )

similarly , second mixture is obtained by mixing them in ratio of 7:3

so linear equation can be written as:

7(x%)+3(y%) = 10(16.7%)

.07x +.03y = 1.67     (equation 2)

solving equations 1 and 2  we get

x =  23 and y = 2

so concentration of solution A = 23%

and concentration of solution B = 2%

That's the final answer

Hope it was helpful !!

step-by-step explanation:

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11