How can i find the factor of

3z(3w - 2)(3w + 2)(9w² + 4)

Step-by-step explanation:

take out a common factor 3z from both terms

= 3z(81 - 16)

81 - 16 ← is a difference of squares

• a² - b² = (a - b)(a + b)

81 = (9w²)² → a = 9w² and 16 = 4² → b = 4

= 3z(9w² - 4)(9w² + 4)

9w² - 4 ← is also a difference of squares with a = 3w and b = 2

= 3z(3w - 2)(3w + 2)(9 + 4)

tangent

step-by-step explanation:

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1