Write the equation of a line that passes through the points (0, -2) and (4, -5). answer must be in standard form: ax + by = c.

The slope-intercept form:

m - slope

b - y-intercept → (0, b).

We have the points (4, -5) and (0, -2) → y-intercept → b = -2.

The formula of a slope:

Substitute:

Therefore we have the equation of a line

Convert to the standard form:

So for this, I will be putting the equation into slope-intercept form then rearranging it into standard form. Firstly, we need to solve for the slope. To do this, take the 2 coordinates given to us and solve as such:

Now, one of the coordinates given to us is (0,-2), which is the y-intercept. With all this info, our slope-intercept equation is . From here we can solve for the standard form.

Firstly, add 3/4x onto both sides of the equation:

Now, it may appear that we are finished. However, 3/4 is not an integer (Integers are whole numbers). To make it an integer, we need to multiply both sides by 4:

In short, the standard form of this equation is 3x + 4y = -8.

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)