Cos(−θ)=√3/4 , sinθ< 0 what is the value of sinθ ?

Two answers are given because the question is "unexpected." cos(θ) = √(3/4) is more commonly seen in such problems than is cos(θ) = (√3)/4, which is what you have written here. Choose the answer that matches your intent.

Step-by-step explanation:

The cosine function is an even function, so cos(θ) = cos(-θ).

The relationship between sin(θ) and cos(θ) is ...

... sin(θ) = ±√(1 -cos(θ)^2)

For sin(θ) < 0 and cos(θ) = (√3)/4, ...

... sin(θ) = -√(1 -3/16) = -√(13/16)

... sin(θ) = -(√13)/4

For sin(θ) < 0 and cos(0) = √(3/4), ...

... sin(θ) = -√(1 -3/4) = -√(1/4)

... sin(θ) = -1/2

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

you are uyytr tyy

step-by-step explanation: