Afruit stand has to decide what to charge for their produce. they need $10 for 4 apples and 4 oranges. they also need $12 for 6 apples and 6 oranges. we put information into a system of linear equations.

4a+4r = 10

6a + 6r = 12

No solutions

Step-by-step explanation:

a = cost of the apple

r = cost of the orange

4a+4r = 10

6a + 6r = 12

Divide the first  equation by 2 and the second equation by 6

2a+2r = 5

a +r = 2

Multiply the second equation by -2 so we can eliminate a

-2a -2r = -4

Add the first equation

2a+2r = 5

-2a -2r = -4

0 = 1

This system is inconsistent and has no solutions

im not quite sure if this is right but i got 5.6 oisutuve

step-by-step explanation:

d) 48

step-by-step explanation:

16,32,48,64,80,96,112,128,144,160,176,192,208,224,240,256,272,288,304,320,336