Find the equation of a line with the given points.(put your answers in the form y=mx+b)(6,2)(5,5)

The slope-intercept form: y= mx + b

m - slope

b - y-intercept

The formula of a slope:

We have the points (6, 2) and (5, 5). Substitute:

Therefore we have y = -3x + b.

Put the coordinates of the point (5, 5) to the equation:

5 = -3(5) + b

5 = -15 + b     add 15 to both sides

20 = b

y = -3x + 20

Step-by-step explanation:

(a) Slope

The point-slope formula for a straight line is

y₂ - y₁ = m(x₂ - x₁)     Insert the points  

2 - 5 = m(6 - 5)

    -3 = m×1

    m = -3

(b) y-intercept

y₂ - y₁ = m(x₂ - x₁)

y₂ - 5 = -3(x₂ - 5)     Remove parentheses

y₂ - 5 = -3x₂ - 15       Add 5 to each side

      y = -3x + 20

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

step-by-step explanation:

what was your answer?