Which real numbers are zeroes of the function f(x)=2x^3-x^2-8x+4

2, -2 and 1/2

Step-by-step explanation:

As the the first coefficient is 2 and the last number is 4  1/2, 2, -2 seem likely zeros ( By the rational roots theorem).

f(2) =  2*8 - 4 -16 + 4 = 0 so 2 is a zero.

f(-2) = -16 - 4 +16 + 4 = 0  so -2 is a zero

f(1/2) = 2*1/8 - 1/4 - 4 + 4 = 0 so 1/2 is the other zero.

Since the highest degree is 3  the maximum number of zeroes is 3.

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )