What is the value of c when the value of the expression 2(3–5c) is 1 less than the value of the expression 4(1–c)?

The answer in fraction form is c = 1/2

The answer in decimal form is c = 0.5

Explanation:

Saying "A is 1 less than B" means A = B-1. So whatever B is, subtract 1 from it and you get the value of A.

Replace A with the expression 2(3-5c). Replace B with 4(1-c)

We go from this

A = B - 1

to this

2(3-5c) = 4(1-c) - 1

Let's isolate c

2(3-5c) = 4(1-c) - 1

2(3)+2(-5c) = 4(1)+4(-c) - 1

6-10c = 4 - 4c - 1

6-10c = 3 - 4c

6-3 = -4c+10c

3 = 6c

6c = 3

c = 3/6

c = 1/2

c = 0.5

9

step-by-step explanation:

8

step-by-step explanation:

just put √(2) * √(32) into a calculator. that will make the answer be 8.