Arectangle has a perimeter of 76 cm and length 31 cm what is its width

The formula for the perimeter of a rectangle is P = 2L + 2W

you are given P (perimeter) and l (length.

Replace the letters withe the given information and solve for width:

76 = 2(31) +2W

Simplify:

76 = 62 + 2w

Subtract 62 from both sides:

14 = 2w

Divide both sides by 2:

W = 14/2

W = 7 cm

The width is 7 cm.

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)