Nina made two investments: investment \text{a}a has a value of \$50$50 at the end of the first year and increases by 8\%8% per year. investment \text{b}b has a value of \$60$60 at the end of the first year and increases by \$3$3 per year. nina checks the value of her investments once a year, at the end of the year. what is the first year in which nina sees that investment \text{a}a's value exceeded investment \text{b}b's value?

6 years

Step-by-step explanation:

Given,

The amount of investment A  = $ 50,

Annual rate of interest = 8 %,

Thus, her amount after x years,

Now, the amount of investment B = $ 60,

Added amount per year = $ 3,

⇒ Added amount in x years = 3x,

Thus, Total amount after x years,

Since, Investment A's value exceeded investment B's value,

If,

By the below graph,

We found that,

x > 5.552

Hence, the first year at which the Investment A's value exceeded investment B's value is 6 years ( approx )

what are the things "represented below"?

step-by-step explanation:

nobody can if you dont give the choices

a precentage of 6th graders. the population is all 6th graders. let me know if i'm wrong, i hope this ! : )

step-by-step explanation: