What is the general equation of a circle centered at the origin?

It is x2+y2−169=0.

Explanation:

The circle you are looking fore is composed by all the points with a distance from the origin of 13/ The distance of a point from the center is

d=√x2+y2 and this distance has to be 13, so

13=√x2+y2 and to obtain the equation we can do the square

132=x2+y2 and the final equation is

x2+y2−169=0.

i got 10.28 but that rounds up to 10.3

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is